1892 United States presidential election in Pennsylvania

1892 United States presidential election in Pennsylvania

← 1888 November 8, 1892 1896 →
 
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Whitelaw Reid Adlai Stevenson
Electoral vote 32 0
Popular vote 516,011 452,264
Percentage 51.45% 45.09%

County Results

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Pennsylvania took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose 32 representatives, or electors to the Electoral College, who voted for president and vice president.

Pennsylvania voted for the Republican nominee, incumbent President Benjamin Harrison, over the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term. Harrison won Pennsylvania by a margin of 6.36%; however, this remains the last occasion a Democratic candidate has ever won northeastern Wayne County, which had regularly voted Democratic during the Third Party System.[1]

With 51.45% of the popular vote, Pennsylvania would prove to be Harrison's fourth strongest victory in terms of percentage in the popular vote after Vermont, Maine and Massachusetts.[2]

  1. ^ The Political Graveyard; Wayne County, Pennsylavania
  2. ^ "1892 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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